If 3 cot x = 4, then what is the value of (5 sin x + 3 cos x)/(5 sin x - 3 cos x)? We are given 3 cot x = 4, or cot x = 4/3. Now consider a right angled triangle, ABC, with BC as the base , right ...

Bạn đang xem: Telangana eamcet engineering 6 years solved papers 2021

We can write cot(x)=cos(x) /sin(x) . Now we have to lớn find for what value of x cos(x) = 0. Cos(x) = 0 for x = <(2n-1)/2>PI where n=1,2,3,……..n. So simply cot(x) = 0 have infinitely many solution in ...
https://math.stackexchange.com/questions/1955179/trigonometry-5-sin-x-cos-y4-cos-x-sin-y-0-cot-x-2-need-to-find-cot-y
Here's what you did wrong: You drew a right angled triangle with an angle x. Then you just went & guessed that the other angle was the y you needed to lớn find. Your guess was wrong.
This kind of equations which phối polynomial and trigonometric terms bởi vì not, in general, show solutions which have a closed khung expression và almost only numerical methods would solve the problem. ...

Xem thêm: Hummus Là Gì ? 8 Lý Do Để Ăn Nó Mỗi Ngày! Hummus Là Gì

Nghi N. Jul 6, 2015displaystylecotx=frac1 anx=-1- o anx=-1 Trig table gives -->displaystylex=frac3pi4or 135 deg
x, equals, start fraction, 3, pi, divided by, 4, end fractionor 135 deg" role="text" class="MathExpression_mathExpression__22QI1 ">
Solve f(x) = cot x = -2Explanation:Calculator gives -> displaystylecotx=frac1 anx=-2 o anx=-frac12 ox=-26.57deg (Quadrant IV)Trig unit circle ...
cotangent, x, equals, start fraction, 1, divided by, tangent, x, over fraction, equals, minus, 2, o, tangent, x, equals, minus, start fraction, 1, divided by, 2, over fraction, o, x, equals, minus, 26, point, 57deg (Quadrant IV)Trig unit circle ..." role="text" class="MathExpression_mathExpression__22QI1 ">
More Items

left< eginarray l l 2 và 3 \ 5 và 4 endarray ight> left< eginarray l l l 2 và 0 & 3 \ -1 & 1 và 5 endarray ight>

EnglishDeutschEspañolFrançaisItalianoPortuguêsРусский简体中文繁體中文Bahasa MelayuBahasa Indonesiaالعربية日本語TürkçePolskiעבריתČeštinaNederlandsMagyar Nyelv한국어SlovenčinaไทยελληνικάRomânăTiếng Việtहिन्दीঅসমীয়াবাংলাગુજરાતીಕನ್ನಡकोंकणीമലയാളംमराठीଓଡ଼ିଆਪੰਜਾਬੀதமிழ்తెలుగు